At 1 atmospheric pressure, 1.000 g of water having a volume of `1.000 cm^3` becomes 1671 `cm^3` of steam when boiled. The heat of vaporization of water at 1 atmosphere is `539 cal//g` . What is the change in internal energy during the process ?

At 1 atmospheric pressure, 1.000 g of water having a volume of `1.000

1.	At 1 atmospheric pressure, 1.000 g of water having a volume of `1.000 cm^3` becomes 1671 `cm^3` of steam when boiled. The heat of vaporization of water at 1 atmosphere is `539 cal//g` . What is the change in internal energy during the process ?
Answer» Heat spent during vaporisation Q = mL = `1.000 xx 539` = 539 cal Work done `W = p(V_(v) - V_(l))` `=1.013 xx 10^(5) xx (1671 - 1.000( xx 10^(-6)` `169.2J = (169.2)/(4.18) cal = 40.5 cal` `therefore` Change in internal energy, U = 539 cal `- 40.5` cal = 498.5 cal

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At 1 atmospheric pressure, 1.000 g of water having a volume of `1.000 cm^3` becomes 1671 `cm^3` of steam when boiled. The heat of vaporization of water at 1 atmosphere is `539 cal//g` . What is the change in internal energy during the process ?

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