 
                 
                InterviewSolution
 Saved Bookmarks
    				| 1. | Two identical conducting rods AB and CD are connected to a circular conducting ring at two diametrically opposite points B and C, the radius of the ring is equal to the length of rods AB and CD. The area of cross-section, thermal conductivity of the rod and ring are equal. points A and D are maintained at temperatures of `100^(@)C` and `0^(@)C`. temperature at poimt C will be A. `62^(@)C`B. `37^(@)C`C. `28^(@)C`D. `45^(@)C` | 
| Answer» Correct Answer - C `R_(AB) = R_(CD)=R`(say) Length of semicircle = `pil` Resistance of semicircle = `piR` as `Ralphal` `R_(BC) = (piR)/2`(in parallel) Heat current, H = `(100-0)/(R+R+(pi)/2.R)=28/R` units Now, `theta_(C) - 0^(@)` = HR = `28^(@)`C `theta_(C)` = `28^(@)`C | |