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    				| 1. | The thickness of a metallic plate is 0.4 cm. The temperature between its two surfaces is `20^(@)C`. The quantity of heat flowing per second is 50 calories from `5cm^(2)` area. In CGS system, the coefficient of thermal conductivity will beA. 0.4B. 0.6C. 0.2D. 0.5 | 
| Answer» Correct Answer - C Heat flowing per second, `Q/t=(KA(DeltaT))/t rArr 50 = (5 xx20K)/0.4rArrK = 1/5=0.2` | |