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At 10:00 Am 2 Trains Started Travelling Towards Each Other From Station 287 Miles Apart They Passed Each Other At 1:30 Pm The Same Dayy .if Average Speed Of The Faster Train Exceeded By 6 Miles /hr What Is Speed Of Faster Train In Miles/hr? |
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Answer» Lets assume the SPEED of slower train = x miles/hrs. So, speed of FASTER train is = (x+6) miles/hrs. Given, passed each other at 1:30 PM i.e after 3 1/2 hrs. Both train travelling towards each other so total RELATIVE speed = x+(x+6) = (2x+6) So, 287/(2x+6) = 7/2 => 574 = 14x + 42 => 14x = 542 => x = ~38 So spee of faster train = (x+6) miles/hrs. = 44 miles/hrs. Lets assume the speed of slower train = x miles/hrs. So, speed of faster train is = (x+6) miles/hrs. Given, passed each other at 1:30 PM i.e after 3 1/2 hrs. Both train travelling towards each other so total relative speed = x+(x+6) = (2x+6) So, 287/(2x+6) = 7/2 => 574 = 14x + 42 => 14x = 542 => x = ~38 So spee of faster train = (x+6) miles/hrs. = 44 miles/hrs. |
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