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At `25^(@)C K_(b)` for `BOH=1.0xx10^(-12).0.01M` solution of `BOH` has `[OH^(-)]`:A. `1.0xx10^(-6) M`B. `1.0xx10^(-7) M`C. `1.0xx10^(-5) M`D. `2.0xx10^(-6) M` |
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Answer» Correct Answer - B `[OH^(-)]=C alpha= Csqrt((K_(b))/(C))` `=sqrt(K_(b).C)=sqrt(1.0xx10^(-12)xx0.01)=1.0xx10^(-7) M` |
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