At `25^(@)C`, the rate constant for the reaction `I^(-) + ClO^(-) rarr IO^(-) + Cl^(-)` is `0.0606 "litre mol"^(-1) sec^(-1)`. If a solution is intially `1.0 M` in `I^(-)` and `5.0 xx 10^(-4) M` in `ClO^(-)`. Can you calculate the `[CO^(-)]` after `300 sec`? If yes, then how much ? If no, then why ?

At `25^(@)C`, the rate constant for the reaction `I^(-) + ClO^(-) rarr

1.	At `25^(@)C`, the rate constant for the reaction `I^(-) + ClO^(-) rarr IO^(-) + Cl^(-)` is `0.0606 "litre mol"^(-1) sec^(-1)`. If a solution is intially `1.0 M` in `I^(-)` and `5.0 xx 10^(-4) M` in `ClO^(-)`. Can you calculate the `[CO^(-)]` after `300 sec`? If yes, then how much ? If no, then why ?
Answer» No doubt the unit of rate constant shows that it is II order. But it is necessary to know the rate law expression which from the statement of the problem, colud be any of the following (given below): Rate `=K[I][ClO^(-)]` or Rate `=K[I^(-)]^(2)` or Rate `=K[ClO^(-)]^(2)`

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