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At `27^@C` latent heat of `I^-` fusion of a compound is `2.7xx10^3 J mol^(-1)`. Calculate the entropy change during fusion.A. `9.77 JK^(-1) "mol"^(-1)`B. `10.73 JK^(-1)"mol"^(-1)`C. `2930 JK^(-1)"mol"^(-1)`D. `108.5 JK^(-1)"mol"^(-1)` |
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Answer» Correct Answer - A Entropy , `DeltaS_(f) =(DeltaH_(f))/(T_(f))=("Fusion enthalpy")/("Temperature")` `DeltaS_(f)=(2930 J "mol"^(-1))/(300 K)=9.77 JK^(-1) "mol"^(-1)` |
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