InterviewSolution
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InterviewSolution
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At a depth of 500m in an ocean (a) what is the absolute pressure? (b) What is the gauge pressure? Density of sea water is `1.03 xx 10^(3) kg//m^(3), g=10ms^(-2)`. Atmospheric pressure = ` 1.01 xx 10^(5)Pa`. |
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Answer» Here,`h=500m, rho = 1.03 xx 10^(3) kgm^(-3)` (a) Absolute pressure, `P=P_(u)+h rho g = 1.01 xx 10^(5)+500xx(1/03xx10^(3))xx10` or, `P=1.01 xx 10^(5) + 51.5 xx 10^(5)=52.51 xx 10^(5)-(52.51 xx 10^(5))/(1.01 xx 10^(5)) = 52 atm` (b) Gauge pressure `P_(G)=P-P_(a)=(p_(a)+h rho g)-P_(a)` `=h rho g = 500 xx (1.03 xx 10^(3)) xx 10 = 51.5 xx 10^(5) Pa= (51.5 xx 10^(5))/(1.01 xx 10^(5))~~51 atm`. |
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