At a distance of `5 cm and 10 cm` outward from the surface of a uniformly charged solid sphere, the potentials are `100 V and 75 V`, repectively. Then.A. Potential at its surface is `150 V`B. the charge on the sphere is `(5//3) xx 10^-10 C`C. the electric field on the surface is `1500 Vm^-1`D. the electric potential at its center is `0 V`

At a distance of `5 cm and 10 cm` outward from the surface of a unifor

1.	At a distance of `5 cm and 10 cm` outward from the surface of a uniformly charged solid sphere, the potentials are `100 V and 75 V`, repectively. Then.A. Potential at its surface is `150 V`B. the charge on the sphere is `(5//3) xx 10^-10 C`C. the electric field on the surface is `1500 Vm^-1`D. the electric potential at its center is `0 V`
Answer» Correct Answer - a.,c. `V = (1)/(4 pi epsilon_0) q/((R + d))` `R` is radius, and `d` is distance from surface `100 = K q/((R + 5) xx 10^-2))`…(i) `75 = K q/((R + 10) xx 10^-2))` ….(ii) From (i) and (ii). `R = 10 cm` and `Q = (50)/(3) xx 10^-10 C` Potential at surface is `V_0 = (k Q)/(R) = (9 xx 10^9 xx 50)/(10 xx 10^-2 xx 3) xx 10^-10 = 150 V` Electric field on surface is `E_0 = (k Q)/(R^2) = 1500 Vm^-1` Potential at the center is `V_C = (3)/(2) V_0 = 225 V`.

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