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At any point of a curve `sqrt(("subnormal")/("subtangent")) ` is equal toA. the abscissa of that pointB. the ordinate of that paintC. slope of the tangent at that pointD. slope of the normal at that point |
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Answer» Correct Answer - C We have, Sub normal `=y (dy)/(dx), " Sub-tangent" = (y)/((dy)/(dx))` `rArr sqrt(("sub normal")/("sub tangent"))=sqrt((y(dy)/(dx))/((y)/((dy)/(dx))))=(dy)/(dx) =` Slope of the tangent |
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