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At one time, the metre was defined as 1650763.73 wavelengths of the orange light emitted by a light source containing `Kr^(86)` atoms. What is the corresponding photon energy of this radiation?A. `3.28 xx 10^(-19)` J/quantaB. `1.204 xx 10^(-31)` J/quantaC. `1.09xx10^(-27)` J/quantaD. `4.01 xx 10^(-40)` J/quanta |
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Answer» Correct Answer - A Given, `bar(v)=1650763.73m^(-1)` Now, `E=hcbar(v)` `=(6.626xx10^(-34))xx(3xx10^(8))xx1650763.73` `=3.28 xx10^(-19)J//"quanta"` |
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