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At `t=0`, number of radioactive nuclei of a radioactive substance are x and its radioactivity is y. Half-life of radioactive substance is T. Then,A. (a) `x/y` is constant throughoutB. (b) `x/ygtT`C. (c) value of `xy` remains half after one half-lifeD. (d) value of `xy` remains one fourth after one half-life |
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Answer» Correct Answer - A::B::D `y=lambdax=(1n2)/(T).x` `x/y=1/lambda=constant` `x/y=(T)/(1n2)` or `x/ygtT` (as `1n2=0.693)` Further, `xy=x(lambdax)=lambdax^2` After one half-life, x remains half. Hence, `x^2` remains `1/4th`. |
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