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At T (K) , if the rate constant of a first order reaction is `4.606xx10^(-3)s^(-1)`, the time to reduce the initial concentration of the reactant to `(1)/(10)` in seconds is :A. 500B. 1000C. 100D. 50 |
Answer» For first order reaction : `k=(2.303)/(t)log.([R_(0)])/([R_(t)])` `4.606xx10^(-3)=(2.303)/(t)log.((1)/(1//10))` `t=(2.303)/(4.606xx10^(-3))=500 sec` |
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