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At the point of intersection of the two curves shown, the conc. of `B` is given by ……… for, `A rarr nB`: A. `(nA_(0))/2`B. `A_(0)/(n-1)`C. `(nA_(0))/(n+1)`D. `((n-1)/(n+1))A_(0)` |
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Answer» Correct Answer - c From fig., `[A]_("left")=[B]_("formed")=nxx[A]_("decayed")` `:. [A_(0)]e^(-lambdat)=nxxA_(0)[1-e^(-lambdat)]` `:. e^(-lambdat)=n/(n+1)` `:. [B]_("formed")=nxxA_(0)xx[1-n/(n+1)]` `=(nA_(0))/(n+1)` |
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