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At what height above the surface of the earth will the acceleration due to gravity be `25%` of its value on the surface of the earth ? Assume that the radius of the earth is 6400 km . |
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Answer» Given : `g_(h) = 25%` of `g = (25)/(100) xx g = (1)/(4) g`. `g_(h) = g(R/(R + h))^(2)` `1/4 g = g (R/(R+h))^(2)` `:. R/(R + h) = 1/2` [Taking square root on both sides] `2R = R + h` `:. 2R - R = h` `:. h = R` `= 6400 km`. |
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