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The energy of an excited hydrogen atom is `-0.85 eV`. Find the angular momentum of the electron. `(h = 6.63 xx 10^(-34) J.s., pi = 3.142, E_(1) = -13.6 eV)` |
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Answer» Given : `E_(n) = -0.85 eV, E_(1) = - 13.6 eV`. `h = 6.63 xx 10^(-34) J.s.` As we know , `E_(n) = (-13.6)/(0.85)` `n^(2) = 16` `n = 4` Angular momentum `= (nh)/(2pi)` `= (4 xx 6.63 xx 10^(-34))/(2 xx 3.142)` Angular momentum `= 4.22 xx 10^(-34)` joule-sec. |
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