1.

The energy of an excited hydrogen atom is `-0.85 eV`. Find the angular momentum of the electron. `(h = 6.63 xx 10^(-34) J.s., pi = 3.142, E_(1) = -13.6 eV)`

Answer» Given : `E_(n) = -0.85 eV, E_(1) = - 13.6 eV`.
`h = 6.63 xx 10^(-34) J.s.`
As we know , `E_(n) = (-13.6)/(0.85)`
`n^(2) = 16`
`n = 4`
Angular momentum `= (nh)/(2pi)`
`= (4 xx 6.63 xx 10^(-34))/(2 xx 3.142)`
Angular momentum `= 4.22 xx 10^(-34)` joule-sec.


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