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In a potentiometer the balancing length of the wire is found to be `2.5 m` for a cell of e.m.f. `1.5V`. Find the balancing length of the wire fore another cell of e.m.f. `1.2 V` on the same potentiometer. |
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Answer» Given : `E_(1) = 1.5 V, E_(2) = 1.2 V, l_(1) = 2.5 m` As we know , `(E_(1))/(E_(2)) = (l_(1))/(l_(2))` `l_(2) = (E_(2))/(E_(1)) xx l_(1)` ` = (1.2 xx 2.5)/(1.5)` `= 0.4 xx 5` `l_(2) = 2 m` |
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