InterviewSolution
Saved Bookmarks
| 1. |
At what temperature does the reduction of lead oxide to lead by carbon becomes spontaneous? `PbO +C rarr Pb(s) +CO(g)` For the reacion, `DeltaH` and `DeltaS` at `25^(@)C` are `108.4 kJ mol^(-1)` and `190 J K^(-1) mol^(-1)` respectively. |
|
Answer» `DeltaG = DeltaH - T DeltaS = 0` or `T = (DeltaH)/(DeltaS) = (108.4)/(190xx10^(-3) = 570.5K` Reaction will be spontaneous at temperature higher than `570.5K`, |
|