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At what temperature the rms speed of oxygen atom equal to rms speed of helium gas atom at -10^(@)C ? Atomic mass of helium =4 Atomic mass of oxygen =32

Answer»

SOLUTION :`v_(rms)=[(3PV)/(M)]^(1//2)=[(3RT)/(M)]^(1//2)`
Let r.m.s. speed of oxygen is `(v_(rms))_(1)` and of helium is `(v_(rms))_(2)` is equal at TEMPERATURE `T_(1)` and `T_(2)` respectively.
`((v_(rms))_(1))/((v_(rms))_(2))=SQRT((M_(2)T_(1))/(M_(1)T_(2)))`
`[(4T)/(32xx263)]^(1//2)=1`
`T_(1)=(32xx263)/(4)=2104k`.


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