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Attempt any SIX : The length of an air column for a fundamental mode in a resonance tube is 16 cm and that for second resonance is 5.25 cm. Find the end correction. |
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Answer» Given : `l_(1) = 16` cm `l_(2) = 50.25` `e = (l_(2)-3l_(1))/(2)` `=(50.25-(3xx16))/(2)` `=(50.25 - 48)/(2)` `e= (2.25)/(2)` `:. E = 1.125 cm` |
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