InterviewSolution
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InterviewSolution
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अवकल समीकरण `(dy)/(dx)=e^(ax)cosy` को हल कीजिये यदि y(0)=0 |
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Answer» `(dy)/(dx)=e^(ax)cosy` `implies(dy)/(cosy)=e^(ax)dx` `impliessecydy=e^(ax)dx` समाकलन से, `intsecydy=inte^(ax)dx+c` `implieslog(secy+tany)=(1)/(a)e^(ax)+c` `impliesalog(secy+tany)=e^(ax)+k" ".......(1)` प्रश्नानुसार, यदि x=0 तब y=0 `impliesalog(sec0+tan0)=e^0+k` `impliesalog(1+0)=1+k` `impliesk=-1` अतः समीकरण (1) से, `alog(secy+tany)=e^(ax)-1` |
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