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अवकल समीकरण `ye^((x)/(y))dx=(xe^((x)/(y))+y^(2))dy(yne0)` का हल ज्ञात कीजिए। |
Answer» दिया गया अवकल समीकरण `ye^((x)/(y))dx=(xe^((x)/(y))+y^(2))dy` है| `implies e^((x)/(y))(dx)/(dy)=(x)/(y)e^((x)/(y))+y` `implies e^((x)/(y))(dx)/(dy)-(x)/(y)e^((x)/(y))=y" ....(1)"` मान लीजिए `(x)/(y)=vimpliesx=vyimplies(dx)/(dy)=v+y(dv)/(dx)` समीकरण (1) से, `e^(v)(v+y(dv)/(dy))-ve^(v)=y` `implies e^(v)y(dv)/(dy)=yimpliese^(v)(dv)/(dy)=1impliese^(v)dv=dy` समाकलन करने पर, `inte^(v)dv=int1dyimpliese^(v)=y+Cimplies e^((x)/(y))=y+C` |
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