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अवकल समीकरणों को हल कीजिये `ye^(x//y)dx=(xe^(x//y)+y)dy` |
Answer» Correct Answer - `e^(x//y)=logcy` `(dy)/(dx)=(ye^(x//y))/(xe^(x//y)+y)implies(dx)/(dy)=(xe^(x//y)+y)/(ye^(x//y))` माना x = vy `implies(dx)/(dy)=v+y(dv)/(dy)` |
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