1.

aX to bY. The initial concentration of X is 0.6 M. After 10 min interval of time the concentration of X and Y are found to be 0.3 M and 0.2 M, respectively. Calculate the stoichiometric coefficients and rate of reaction with respect to X and Y.

Answer»

Solution :`AX to bY`
`{:(0.6,0,"Initial concentration"),(0.3,0.2M, "Final concentration"):}`
`r=(-1)/(a)(Delta[X])/(Delta t)=(1)/(b)(Delta [Y])/(Delta t) implies (-1)/(a)((0.3-0.6))/(10)`
`=(1)/(b)((0.2-0.0))/(10)`
`implies (0.3)/(a)=(0.2)/(b) implies ` Least POSSIBLE VALUES of a and b are 3 and 2, respecitvely
Rate with RESPECT to `X=(Delta[X])/(Delta t)=(0.3)/(10xx60)`
=0.0005 mole/`L^(-1) "SEC"^(-1)`
Rate with respect to `Y=(0.2)/(10xx60)`
`=0.00033 " mole" //L^(-1) "sec"^(-1)`


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