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InterviewSolution
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Ayush starts walking from his house to office, Instead of going to the office directly, he goes to bank first, from there to his daughter’s school and then reaches the office. What is the extra distance travelled by Ayush in reaching the office? (Assume that all distance covered are in straight lines). If the house is situated at (2, 4), bank at (5, 8) school at (13, 14) and office at (13, 26) and coordinates are in kilometer. |
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Answer» The position of Ayush’s house is (2, 4) and the position of the bank is (5, 8). So, the distance between the house and the bank, d1 = √[(5 – 2)2 + (8 – 4)2] = √[(3)2 + (4)2] = √[9 + 16] = √25 = 5 km The position of the bank is (5, 8) and the position of the school is (13, 14). So, the distance between the bank and the school, d2 = √[(13 – 5)2 + (14 – 8)2] = √[(8)2 + (6)2] = √[64 + 36] = √100 = 10 km The position of the school is (13, 14) and the position of the office is (13, 26). So, the distance between the school and the office, d3 = √[(13 – 13)2 + (26 – 14)2] = √[(0)2 + (12)2] = √144 = 12 km Let d be the total distance covered by Ayush d = d1 + d2 + d3 = 5 + 10 + 12 = 27 km Let the D be the shortest distance from Ayush’s house to the office, D = √[(13 – 2)2 + (26 – 4)2] = √[(11)2 + (22)2] = √[121+ 484] = √605 = 24.6 km Thus, the extra distance covered by Ayush = d – D = 27 – 24.6 = 2.4 km |
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