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b. In Young's experiment, the wavelength of lightused is 6000 A, the distance between two slits is0.05 cm and the distance of screen from the slits is1 m. Find out the distance between first dark fringeAns. 0.06 cm.and first bright fringe.

Answer»

fringe width=wavelength xdistance from screen/slit differencehencefringe width=6000*10^-10*1/0.05*10^-2=0.12cmdistance between first dark and bright fringe is=0.12/2=0.06cmas fringe width is the distance in bright to bright hence half of distance



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