1.

B. When two resistors are connectedin series, their effective resistanceis 80 S2. When they are connectedin parallel, their effective resistanceis 20 Ω. What are the values of thetwo resistances?Answer : 40 Ω , 40 Ω)

Answer»

When connected in series R₁ + R₂ = 80 Ω ………[1]

When connected in parellelR₁R₂ / (R₁ + R₂) = 20 Ω ………[2]

Equation [2] can also be written asR₁R₂ / 80 = 20 ………[∵ From (1)]R₁R₂ = 1600 R₁ = 1600 / R₂

Substitute this value in equation [1](1600 / R₂) + R₂ = 80R₂² - 80R₂ + 1600 = 0

Solve above polynomial equationWe will get R₂ = 40 ΩIf R₂ is 40 Ω then from equation [1] R₁ is also 40 Ω

Therefore,Values of two resistance is 40 Ω



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