1.

Bajinder runs ten times around a square track and covers 4 km. Find the length of the track.

Answer»

Let a be the side of the square track.

Perimeter of the square track = 4a

Bajinder runs ten times around the square track and covers 4 km.

i.e., 10 × 4a = 4 km

⇒ 40a = 4 × 1000 m [∵ 1 km = 1000 m]

⇒ a = (4 x 100)/40 m = 100 m

∴ Length of the track = 4a

= 4 × 100 m = 400 m


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