1.

Barium chloride reacts with sodium sulphate to form barium sulphate and sodium chloride. In an experiment to verify the law of conservation of mass, 20.8 g of barium chloride reacted with 14.2 g of sodium sulphate to form 11.7g of sodium chloride. The amount of barlum sulphate formed in the above reaction will be ....

Answer»

35.0 G
23.7 g
23.3 g
23.0 g

Solution :23.3 g


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