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Barium chloride reacts with sodium sulphate to form barium sulphate and sodium chloride. In an experiment to verify the law of conservation of mass, 20.8 g of barium chloride reacted with 14.2 g of sodium sulphate to form 11.7g of sodium chloride. The amount of barlum sulphate formed in the above reaction will be .... |
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Answer» 35.0 G |
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