Base of a triangle is 9 and height is 5. Base of another triangle is 1

1.	Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles.
Answer» Let the base, height and area of the first triangle be b₁ , h₁ , and A₁ respectively. Let the base, height and area of the second triangle be b₂ , h₂ and A₂ respectively. A₁/A₂ = (b₁ x h₁)/(b₂ x h₂) ...[Ratio of areas of two tringles is equal to the product of their bases and corresponding ] A₁/A₂ = (9 x 5)/(10 x 6) = 45/60 A₁/A₂ = 3/4 ∴ The ratio of areas of the tringles is 3:4.

Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles.

Answer»

Let the base, height and area of the first triangle be b₁ , h₁ , and A₁ respectively. Let the base, height and area of the second triangle be b₂ , h₂ and A₂ respectively.

A₁/A₂ = (b₁ x h₁)/(b₂ x h₂) ...[Ratio of areas of two tringles is equal to the product of their bases and corresponding ]

A₁/A₂ = (9 x 5)/(10 x 6)

= 45/60

A₁/A₂ = 3/4

∴ The ratio of areas of the tringles is 3:4.

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Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles.

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