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`Be^(3+)` and a proton are accelerated by the same potential, their de`-` Broglie wavelengths have the ratio ( assume mass of proton `=` mass of neutron `) :`A. `1:2`B. `1:4`C. `1:1`D. `1:3sqrt(3)` |
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Answer» Correct Answer - 4 `lambda_(Be^(+3))=(h)/(sqrt(2xx3eVm_(Be^(3+))))=(h)/(sqrt(2xx3eV9m_(p)))` `lambda_(p)=(h)/(sqrt(2eVm_(p)))` Hence `(lambda_(Be^(+3)))/(lambda_(p))=sqrt((2eVm_(p))/(2xx3eVxx9m_(p)))=(1)/(3sqrt(3))` |
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