Before the thunder stand on end Ahir with mass 0.50 mg and 1.0 PC

1.	Before the thunder stand on end Ahir with mass 0.50 mg and 1.0 PC
Answer» $\huge{\underline{\mathtt{\blue{A}\red{<klux>N</klux>}\pink{S}\green{W}\purple{E}\orange{R}}}}$ EXPLANATION: The electric force is equal to the weight. Electric force = Weight Eq = MG Electric field STRENGTH E = mg / Q {mass should be in kg.} E = (0.5×10-6) × 9.81 / (1.0×10-12) E = 4.9×106 N C-1

Answer»

$\huge{\underline{\mathtt{\blue{A}\red{<klux>N</klux>}\pink{S}\green{W}\purple{E}\orange{R}}}}$

EXPLANATION:

The electric force is equal to the weight.

Electric force = Weight

Eq = MG

Electric field STRENGTH E = mg / Q

{mass should be in kg.}

E = (0.5×10-6) × 9.81 / (1.0×10-12)

E = 4.9×106 N C-1

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Before the thunder stand on end Ahir with mass 0.50 mg and 1.0 PC​

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Before the thunder stand on end Ahir with mass 0.50 mg and 1.0 PC