InterviewSolution
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Below Is A Pseudo Code Read X? |
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Answer» GIVEN Last value INT seq. = 54. and in EVERY Loop result multiplied By 3. So By Backward Approach 54/3=18 => 18/3=6 => 6/3=2. So, The Starting Value Is 2. Given Last value int seq. = 54. and in every Loop result multiplied By 3. So By Backward Approach 54/3=18 => 18/3=6 => 6/3=2. So, The Starting Value Is 2. |
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