Benzene burns according to the following equations at 300K (R=8.314 J `"mole"^(-1)K^(-1))` `2C_(6)H_(6)(l) + 15O_(2)(g) rarr 12 CO_(2)(g) + 6H_(2)O(l) " " DeltaH^(@) =- 6542 KJ` What is the `DeltaE^(@)` for the combustion of 1.5 mol of benzeneA. `-3271 KJ`B. `-9812 KJ`C. `-4906.5 `KJD. None of these

Benzene burns according to the following equations at 300K (R=8.314 J

1.	Benzene burns according to the following equations at 300K (R=8.314 J `"mole"^(-1)K^(-1))` `2C_(6)H_(6)(l) + 15O_(2)(g) rarr 12 CO_(2)(g) + 6H_(2)O(l) " " DeltaH^(@) =- 6542 KJ` What is the `DeltaE^(@)` for the combustion of 1.5 mol of benzeneA. `-3271 KJ`B. `-9812 KJ`C. `-4906.5 `KJD. None of these
Answer» Correct Answer - D From given reaction `Deltan_(g) =12 -15=-3` so `DeltaE^(@) =DeltaH^(@)-Deltan_(g)RT =-6542 + 3RT` for 1.5 mole , `Delta E^(@) =(1.5)/(2) {-6542 + 3RT} = 4900 KJ`

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