block of mass 10 kg is placed on a vertical spring (attached to a fixed end at the bottom) which is compressed to a certain length and then released so that the block rises to a height of 3m. Find the PE stored in compressed spring, [g = 10 m / s² ]

block of mass 10 kg is placed on a vertical spring (attached to a fixe

1.	block of mass 10 kg is placed on a vertical spring (attached to a fixed end at the bottom) which is compressed to a certain length and then released so that the block rises to a height of 3m. Find the PE stored in compressed spring, [g = 10 m / s² ]
Answer» Given data,Mass of the body is ( m ) =2Kgspring's constant (K)=1960N/mheight of the body =0.4mLet the maximum distance SPRING will compressed =xm initial potential energy of body =MG(h+x)final potential energy = spring potential energy = 21 Kx 2 ACCORDING to the LAW of conservation of energy,initial potential energy = final potential energy mg(h+x)= 21 Kx 2 2mgh+2mgx=Kx 2 Kx 2 −2mgx−2mgh=0 ⇒1960x 2 −2×2×9.8×x−2×2×9.8×0.4=0⇒1960x 2 −39.2x−15.68=0 after solving this quadratic equations , we get x=0.1m HENCE, answer is x=0.1m

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block of mass 10 kg is placed on a vertical spring (attached to a fixed end at the bottom) which is compressed to a certain length and then released so that the block rises to a height of 3m. Find the PE stored in compressed spring, [g = 10 m / s² ]​

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block of mass 10 kg is placed on a vertical spring (attached to a fixed end at the bottom) which is compressed to a certain length and then released so that the block rises to a height of 3m. Find the PE stored in compressed spring, [g = 10 m / s² ]