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Body is thrown from a point with a speed 50 metre per second at an angle 37 degree with horizontal when it has moved a horizontal distance of 80 metre then its distance from the projection |
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Answer» A body is thrown from a POINT with SPEED 50m/s at am angle 37° with HORIZONTAL. a/c to question, body moves 80m in horizontal direction. let's find how much TIME taken to move 80m in horizontal direction. so, initial velocity of body along horizontal direction is , we know, cos37° = 4/5 so, ux = 50 × 4/5 = 40m/s and acceleration along horizontal direction , ax = 0 now using formula, or, 80 = 40t => t = 2sec now find distance travelled during 2 sec in vertical direction. initial velocity of body along vertical direction, [u_y=50sin37^{\circ}[/tex] = 50 × 3/5 = 30 [as sin37° = 3/5 ] now using formula, = 30 × 2 + 1/2 × (-10) × (2)² = 60 - 20 = 40m hence, distance travelled by body in vertical direction is 40m |
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