Bond energies can be obtained by using the following relation: `DeltaH (reaction) = sum`Bond energy of bonds, broken in the reactants `-sum` Bond energy fo bonds, formed in the products Bond enegry depends on three factors: a. Greater is the bond length, lesser is the bond enegry. b. Bond energy increases with the bond multiplicity. c. Bond enegry increases with electronegativity difference between the bonding atoms. The heat of formation of `NO` from its elements is `+90 kJ mol^(-1)`, What is the approximate bond dissociation enegry of the bond in `NO`? `BE_(N=N) = 941 kJ mol^(-1) BE_(O=O) = 499 kJ mol^(-1)`A. `630 kJ mol^(-1)`B. `700 kJ mol^(-1)`C. `860 kJ mol^(-1)`D. `810 kJ mol^(-1)`

Bond energies can be obtained by using the following relation: `DeltaH

1.	Bond energies can be obtained by using the following relation: `DeltaH (reaction) = sum`Bond energy of bonds, broken in the reactants `-sum` Bond energy fo bonds, formed in the products Bond enegry depends on three factors: a. Greater is the bond length, lesser is the bond enegry. b. Bond energy increases with the bond multiplicity. c. Bond enegry increases with electronegativity difference between the bonding atoms. The heat of formation of `NO` from its elements is `+90 kJ mol^(-1)`, What is the approximate bond dissociation enegry of the bond in `NO`? `BE_(N=N) = 941 kJ mol^(-1) BE_(O=O) = 499 kJ mol^(-1)`A. `630 kJ mol^(-1)`B. `700 kJ mol^(-1)`C. `860 kJ mol^(-1)`D. `810 kJ mol^(-1)`
Answer» `DeltaH = H_(P) -H_(R)`

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