Bonding in metal carbonyls is represented by the end structures. `overset(M-C-=O" "harr" "M=C=O)(I" "II)` The contribution of I and II to the real structure depends upon the extent of `pi-` back bonding. Both `sigma` donation and `pi-` back bonding are synergitc. The filled orbitals CO overlap with vacant metal d orbitals which is called `sigma` donation. The filled metal d orbitals overlap with `pi` antibondig moleculat orbital of CO. which is called `pi-`back bonding . Which one of the following has the highest C-O bond length?A. `[Cr(CO)_(6)]`B. `[Ti(CO)_(6)]^(2-)`C. `[Mn(CO)_(5)]^(+)`D. `[Fe(CO)_(5)]`

Bonding in metal carbonyls is represented by the end structures. `over

1.	Bonding in metal carbonyls is represented by the end structures. `overset(M-C-=O" "harr" "M=C=O)(I" "II)` The contribution of I and II to the real structure depends upon the extent of `pi-` back bonding. Both `sigma` donation and `pi-` back bonding are synergitc. The filled orbitals CO overlap with vacant metal d orbitals which is called `sigma` donation. The filled metal d orbitals overlap with `pi` antibondig moleculat orbital of CO. which is called `pi-`back bonding . Which one of the following has the highest C-O bond length?A. `[Cr(CO)_(6)]`B. `[Ti(CO)_(6)]^(2-)`C. `[Mn(CO)_(5)]^(+)`D. `[Fe(CO)_(5)]`
Answer» Correct Answer - b More negative charge on Ti atom , which pumps more electrons into `pi^(**)` MO of CO , So bond order decreases , bond length increases.

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