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Coordination number of Cr is six. A complex with ligands `C_(2)O_(4)^(2-)`, en and superoxide will be in the ratio to make complex `[Cr(C_(2)O_(4))_(x)(en)_(y)(O_(2))_(z)]^(Θ)` .A. `1:1:2`B. `1:1:1`C. `1:2:2`D. `2:1:1` |
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Answer» Correct Answer - 1 `C_(2)O_(4)^(-2)` and en are bidentate ligands `O_(2)^(-)` is monodentate ligand. |
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