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The secondary valence of `Co^(-3)` is 6. Calculate the number of moles of AgCl precipitated, when excess of `AgNO_(3)` solution is added to 1.5 lit of 0.2 M. `CoCl_(3). 5 NH_(3)` solution

Answer» SV of `Co^(+3)` is 6 and it will be satisfied by five `NH_(3)` and one `Cl^(-)` the remaining `2Cl^(-)` ions satisfy IV so formula is `[CoCl(NH_(3))_(5)]Cl_(2)`.
1 mole of this complex of this complex gives 2 mole of `Cl^(-)` ions `1.5xx0.2` mole gives how many moles of `Cl^(-)` ions. `(1.5xx0.2)/(1)xx2 = 0.6`moles.


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