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Boolean function to minimum number of literals..a) (x+y)(x+y'). B). x+y+x'z+yz

Answer»

tion:a) (x + y)(x + y')= x.x + x.y' + y.x + y.y'= x + x(y + y') + 0= x + x = xb)x + y +x'Z + yz= x + x'z + y + yz= x + x'z + y(1 + z)= x + z + yProperties useda.a = aa + a' = 1a.a' = 0a + 1 = 1a + a'b = a + bHope it HELPS :-)



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