By simplifying (3)^3/2, we get __________(a) (3)^3/(3)^2(b) (3)^2/(3)^3(c) \(\sqrt{27}\)(d) \(\sqrt[3]{9}\)This question was addressed to me during an interview.This question is from Laws of Exponents for Real Numbers in section Number Systems of Mathematics – Class 9

By simplifying (3)^3/2, we get __________(a) (3)^3/(3)^2(b) (3)^2/(3)^

1.	By simplifying (3)^3/2, we get __________(a) (3)^3/(3)^2(b) (3)^2/(3)^3(c) \(\sqrt{27}\)(d) \(\sqrt[3]{9}\)This question was addressed to me during an interview.This question is from Laws of Exponents for Real Numbers in section Number Systems of Mathematics – Class 9
Answer» The correct option is (c) \(\sqrt{27}\) The EXPLANATION is: ACCORDING to laws of exponents, a^m/n = \((\sqrt[n]{a})^m\). APPLYING that rule here, 3^3/2 = (3^3)^1/2 = 27^1/2 = \(\sqrt{27}\).

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