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1.

What do we get after factorising x^3+ 8y^3+ z^3 – 4xyz?(a) (x + 2y + z) (x^2 + 4y^2 + z^2 – 2xy – 2yz – zx)(b) (x + 2y + z) (x^2 + 4y^2 + z^2 – 2xy – 2yz – zx)(c) (x + 2y + z) (x^2 + 4y^2 + z^2 – 2xy – 2yz – zx)(d) (x + 2y + z) (x^2 + 4y^2+z^2 – 2xy – 2yz – zx)I have been asked this question by my college director while I was bunking the class.This intriguing question originated from Factorisation of Polynomials and Algebraic Identities in division Polynomials of Mathematics – Class 9

Answer»

Correct answer is (c) (X + 2y + z) (x^2 + 4y^2 + z^2 – 2xy – 2YZ – zx)

Explanation: We know that a^3 + b^3 + c^3 – 3ABC = (a+b-c)(a^2 + b^2 + c^2 – ab – bc – ca)

In x^3 + 8y^3 + y^3 – 6xyz, a=x, b=2y and c=z

By using the above EQUATION, we get x^3 + 8y^3 + z^3 – 4xyz = (x+2y+z) (x^2 + (2y)^2 + z^2 – x(2y) – (2y)(z) – zx)

= (x + 2y + z) (x^2 + 4y^2 + z^2 – 2xy – 2yz – zx).

2.

What do we get after expanding (p+3q-2z)^2?(a) p^2 + 9q^2 + 4z^2 + 6pq – 12qz + 4zp(b) p^2 + 9q^2 + 4z^2 + 12pq + 12qz + 4zp(c) p^2 + 9q^2 + 4z^2 – 12pq – 12qz – 4zp(d) p^2 + 9q^2 + 4z^2 + 6pq – 12qz – 4zpThe question was asked in an interview for internship.This key question is from Factorisation of Polynomials and Algebraic Identities in chapter Polynomials of Mathematics – Class 9

Answer»

Right option is (d) p^2 + 9q^2 + 4z^2 + 6PQ – 12qz – 4zp

Explanation: We know that (a+b+C)^2 = a^2 + b^2 + c^2 + 2AB + 2BC + 2ca

(p+3Q-2z)^2can also be written as (p+3q+(-2z))^2.

Here, a = p, b = 3q and c = -2z

Therefore, using that formula we get (p+3q+(-2z))^2

= p^2 + (3q)^2 + (-2z)^2 + 2(p)(3q) + 2(3q)(-2z) + 2(-2z)(p)

= p^2 + 9q^2 + 4z^2 + 6pq – 12qz – 4zp.

3.

95^3 = __________ (calculate without direct calculation).(a) 856395(b) 857625(c) 857375(d) 852395I have been asked this question during an interview.My query is from Factorisation of Polynomials and Algebraic Identities topic in portion Polynomials of Mathematics – Class 9

Answer»

The CORRECT option is (c) 857375

Easy explanation: We know that (x-y)^3 = x^3– y^3 – 3 xy (x-y).

95^3can ALSO be written as (100-5)^3

Therefore, 95^3= (100-5)^3 = (100)^3 – (5)^3 – 3(100)(5)(100-5)

= 1000000125 – 1500(95)

= 1000000 – 125 – 142500

= 857375.

4.

26*34 = __________ (calculate without direct calculation).(a) 900(b) 884(c) 916(d) 844This question was addressed to me during an internship interview.My query is from Factorisation of Polynomials and Algebraic Identities in portion Polynomials of Mathematics – Class 9

Answer»

Right option is (B) 884

To ELABORATE: 26*34 can ALSO be written as (30-4)*(30+4)

We KNOW that (a-b)*(a+b) = a^2 -b^2

Similarly, 26*34 = (30-4)*(30+4)

= 30^2 – 4^2

= 900 – 16

= 884.

5.

27*29 = __________ (calculate without direct calculation).(a) 783(b) 753(c) 763(d) 793I had been asked this question by my school teacher while I was bunking the class.My question comes from Factorisation of Polynomials and Algebraic Identities in division Polynomials of Mathematics – Class 9

Answer» CORRECT ANSWER is (a) 783

The best explanation: We know that (a+b)*(a+c) = a^2 + (b+c)a + bc

27*29 can also be WRITTEN as (25+2)*(25+4)

Now using above identity, 27*29 = (25+2)*(25+4)

= 25^2 + (2+4)25 + (4)(2)

= 625 + 6(25) + 8

= 625 + 150 + 8

= 783.
6.

What do we get after factoring 49x^2-28xy+.4y^2?(a) (7x+2y)^2(b) (49x-4y)^2(c) (7x-2y)^2(d) (7x-28y)^2I got this question in homework.My question comes from Factorisation of Polynomials and Algebraic Identities in section Polynomials of Mathematics – Class 9

Answer» CORRECT OPTION is (c) (7x-2y)^2

The explanation: We know that a^2-2ab+.b^2 = (a-b)^2

49x^2-28xy+.4y^2 can also be written as (7x)^2-2(7)(2)xy+(2y)^2

Here, a = 7x and b = 2y.

Therefore,49x^2-28xy+.4y^2 = (7x)^2-2(7)(2)xy+(2y)^2

= (7x-2y)^2.
7.

What do we get after factorising x^2+6x-27?(a) (x+9)(x-3)(b) (x-9)(x+3)(c) (x-9)(x-3)(d) (x+9)(x+3)This question was posed to me in an international level competition.I would like to ask this question from Factorisation of Polynomials and Algebraic Identities in chapter Polynomials of Mathematics – Class 9

Answer»

Correct choice is (a) (x+9)(x-3)

To elaborate: To factorisex^2+6x-27, we have to FIND TWO numbers ‘a’ and ‘b’ such that a+b=6 and a*b=27.

For that we have to find factors of -27, which are ±1, ±3, ±9.

Now we have to ARRANGE two numbers from these numbers such that a+b=6 and a*b=27.

By considering this, we get two numbers +9 and -3

9 + (-3) = 6 and 9*-3 = -27

Now after manipulating terms, we getx^2+9x- 3x-27.

x^2+9x- 3x-27 = x(x+9)-3(x+9)

= (x+9)(x-3).

8.

Find the value of k, if x-3 is a factor of 5x^3-2x^2+x+k.(a) 50(b) 60(c) -60(d) -120This question was addressed to me at a job interview.The question is from Factorisation of Polynomials and Algebraic Identities in portion Polynomials of Mathematics – Class 9

Answer»

The CORRECT option is (d) -120

The explanation is: According to factor theorem, x-a is a factor of P(x) if p(a) = 0.

Here, it is GIVEN that x-3 is a factor of 5x^3-2x^2+x+k.

Therefore, p(3) must be EQUAL to zero.

p(3) = 5(3)^3-2(3)^2+3+k = 0

Therefore, 5(27) – 2(9) + 3 + k = 0

135 – 18 + 3 + k=0

120 + k = 0

Therefore,k= -120

9.

x^2 + 8x + 16 is a multiplier of x+4.(a) True(b) FalseI have been asked this question during an interview for a job.This interesting question is from Remainder Theorem topic in chapter Polynomials of Mathematics – Class 9

Answer»

The correct choice is (a) True

To explain: p(x) is SAID to be multiplier of x-a if p(a) = 0.

Therefore, CHECKING whether p(-4) is ZERO of p(x) or not.

p(-4) = (-4)^2 + 8(-4) + 16

= 16 – 32 +16

= 32 – 32

= 0

p(-4) = 0, so we can SAY that x^2 + 8x + 16 is a multiplier of x+4.

Or in other words, we can say that there we get “0” as a remainder when we divide x^2 + 8x + 16 by x+4.

10.

x-1 is a factor of 4x^2-9x-6.(a) True(b) FalseThis question was addressed to me in an interview.Question is taken from Factorisation of Polynomials and Algebraic Identities topic in portion Polynomials of Mathematics – Class 9

Answer»

Correct choice is (b) False

Explanation: ACCORDING to factor theorem, x-a is a factor of P(x) if p(a) = 0.

Therefore x-1 is a factor of 4x^2-9x-6 is a factor if p(1)=0.

p(1) = 4(1)^2-9(1)-6 = 4 – 9 – 6

= -11 ≠ 0

Therefore, we can say that x-1 is not a factor of 4x^2-9x-6.

11.

What is the remainder if we divide 6x^3 + x^2 – 2x + 4 by x-2 ?(a) 48(b) 52(c) -26(d) -24This question was addressed to me by my college director while I was bunking the class.I'd like to ask this question from Remainder Theorem in chapter Polynomials of Mathematics – Class 9

Answer»

Correct choice is (b) 52

The best explanation: According to remainder theorem, if p(X) be any polynomial of degree greater than or equal to one and LET “a” be any real number. If p(x) is DIVIDED by the linear polynomial x-a, then the remainder is p(a).

So to know the value of remainder, we have to find the value of p(2).

p(2) = 6(2)^3 + (2)^2 – 2(2) + 4

= 6(8) + 4 – 4 + 4

= 48 + 4

= 52.

12.

\(\frac{(5x^3 + 2x^2 + x)}{x}\) = __________(a) 5x^3 + 2x^2 + 1(b) 5x^4 + 2x^3 + x(c) 5x^2 + 2x^2 + x(d) 5x^2 + 2x + 1I had been asked this question in homework.My question is from Zeroes of Polynomial topic in chapter Polynomials of Mathematics – Class 9

Answer» RIGHT OPTION is (d) 5x^2 + 2x + 1

Explanation: \(\FRAC{(5x^3 + 2x^2 + x)}{x} = \frac{5x^3}{x} + \frac{2x^2}{x} + \frac{x}{x}\)

= 5x^2 + 2x + 1.
13.

What is the zero of p(x) = x^2+6x+9?(a) -3(b) -6(c) -9(d) -2I got this question during an interview.My query is from Zeroes of Polynomial topic in chapter Polynomials of Mathematics – Class 9

Answer»

Correct option is (a) -3

Easy explanation: If p(X) is any POLYNOMIAL, then for “a” to be a zero of the polynomial p(x), p(a) = 0.

Therefore, equating p(x) with 0, we GET x^2+6x+9=0

(x+3)^2 = 0

x+3 = 0

x = -3

Hence, -3 is the zero of the polynomial x^2+6x+9 because p(-3) = 0.

14.

If p(x) = 4x^2+7x-8, then the value of p(2) is __________(a) 20(b) 18(c) 22(d) 14This question was posed to me by my college director while I was bunking the class.My doubt is from Zeroes of Polynomial topic in chapter Polynomials of Mathematics – Class 9

Answer»

Right option is (c) 22

For explanation: If p(x) is any polynomial, then p(a) MEANS substituting x by a in a polynomial.

Therefore, p(2) means, putting 2 in PLACE of x in 4x^2+7x-8.

Hence, p(2) = 4(2)^2+7(2)-8 = 4(4) + 14 – 8

= 16 + 14 – 8

= 22.

15.

How many terms are there in a polynomial 5x^2+2x-2?(a) 1(b) 2(c) 3(d) 4I got this question in an online quiz.The query is from Polynomials in One Variable in section Polynomials of Mathematics – Class 9

Answer»

The correct answer is (c) 3

Easiest explanation: We can GET number of TERMS by separating them by “+” or “–” SIGN.

In the GIVEN polynomial 5x^2+2X-2, if we separate expressions by “+” or “–” sign, we get three separate terms as 5x^2, 2x and 2.

Hence we can say that there are three terms in the polynomial 5x^2+2x-2.

16.

Which of the following is the example of Trinomial?(a) 9x^3+ 5x^2+7x+2(b) 9(c) 7x-2(d) 5x^2+2x-2The question was posed to me by my college professor while I was bunking the class.Question is from Polynomials in One Variable topic in section Polynomials of Mathematics – Class 9

Answer»

The correct answer is (d) 5x^2+2x-2

The best I can explain: Polynomials only having THREE terms are CALLED Trinomials.

Hence to find trinomial POLYNOMIAL, we have to find polynomial which has three terms. We can see that 5x^2+2x-2 has three terms namely 5x^2, 2x and 2. Hence it is trinomial.

Similarly, polynomials only having ONE TERM are called Monomials and polynomials only having two terms are called Binomials.

17.

(x-y)^2 = __________(a) x^2 + 2xy+y^2(b) x^2 – 2xy+y^2(c) x^2 – y^2(d) x^2 + y^2I had been asked this question in examination.I'm obligated to ask this question of Polynomials in One Variable in division Polynomials of Mathematics – Class 9

Answer»

The correct ANSWER is (B) x^2 – 2xy+y^2

Easy EXPLANATION: We can write (x-y)^2 as (x-y) * (x-y) = x^2-xy-yx + y^2

= x^2-2xy + y^2.

18.

A quadratic polynomial can have at most __________ terms.(a) 1(b) 4(c) 2(d) 3I got this question in my homework.This intriguing question originated from Polynomials Basics in portion Polynomials of Mathematics – Class 9

Answer»

The correct ANSWER is (d) 3

The EXPLANATION is: A polynomial of degree 2 is called quadratic polynomial.

Quadratic polynomials are of the form ax^2+BX+c and it can contain at most three terms namely ax^2, bx and c. Thus, we can say that a quadratic polynomial can have at most three terms.

Similarly, a polynomial of degree 1 is called LINEAR polynomial and a polynomial of degree 3 is called CUBIC polynomial.

19.

What is the degree of 0?(a) Not defined(b) 1(c) 2(d) 0The question was posed to me in a national level competition.This question is from Polynomials Basics in chapter Polynomials of Mathematics – Class 9

Answer»

The correct answer is (a) Not DEFINED

To EXPLAIN: Degree of the ZERO POLYNOMIAL is not defined.

Zero polynomial is denoted by 0, and degree for that is not defined.

20.

What is the degree of a polynomial 7?(a) 7(b) 1(c) 0(d) 2The question was asked in an interview for internship.The above asked question is from Polynomials Basics in division Polynomials of Mathematics – Class 9

Answer»

Right choice is (C) 0

Explanation: DEGREE of a non-zero constant polynomial is zero.

We can see that given polynomial 7 CONTAIN only ONE term and that is constant. 7 can also be written as 7x^0.

Hence degree of 7 is zero.

21.

\(\frac{1}{\sqrt[2]{x}}\) is a polynomial.(a) True(b) FalseThe question was asked in an interview.This intriguing question comes from Polynomials Basics in chapter Polynomials of Mathematics – Class 9

Answer»

Correct OPTION is (B) False

The BEST I can explain: For an expression to be a polynomial, exponent of variable has to be whole NUMBER.

\(\frac{1}{\sqrt[2]{x}}\) can be written as x^-1/2. We can see that exponent of x is -1/2 which is not whole number (W = {0, 1, 2, 3…}). Hence, \(\frac{1}{\sqrt[2]{x}}\) is not a polynomial.

22.

What is the degree of a polynomial of 4x^7+9x^5+5x^2+11?(a) 7(b) 4(c) 5(d) 2The question was asked in an internship interview.My query is from Polynomials Basics topic in chapter Polynomials of Mathematics – Class 9

Answer»

Correct choice is (a) 7

The best EXPLANATION: Degree of a polynomial is the HIGHEST power of variable in a polynomial.

The TERM with the highest power of x is 4x^7 and EXPONENT of x in that term is 7, so the degree of polynomial of 4x^7+ 9x^5+5x^2+11 is 7.

23.

What is the coefficient of x^3 in a polynomial 6x^4 + 3x^2 + 8x + 5?(a) 6(b) 3(c) 8(d) 0I got this question by my school teacher while I was bunking the class.Question is taken from Polynomials Basics topic in chapter Polynomials of Mathematics – Class 9

Answer»

Correct answer is (d) 0

The EXPLANATION: Coefficient is the NUMBER which is multiplied with respective variable.

In the given POLYNOMIAL 6x^4 + 3x^2 + 8x + 5, there is not an expression containing x^3. So we can write 6x^4+ 3x^2+8x+5 as 6x^4 + 0x^3 + 3x^2 + 8x + 5. We can SEE that 0 is multiplied with expression x^3, so coefficient of x^3 is 0.