What do we get after factorising x^2+6x-27?(a) (x+9)(x-3)(b) (x-9)(x+3)(c) (x-9)(x-3)(d) (x+9)(x+3)This question was posed to me in an international level competition.I would like to ask this question from Factorisation of Polynomials and Algebraic Identities in chapter Polynomials of Mathematics – Class 9

What do we get after factorising x^2+6x-27?(a) (x+9)(x-3)(b) (x-9)(x+3

1.	What do we get after factorising x^2+6x-27?(a) (x+9)(x-3)(b) (x-9)(x+3)(c) (x-9)(x-3)(d) (x+9)(x+3)This question was posed to me in an international level competition.I would like to ask this question from Factorisation of Polynomials and Algebraic Identities in chapter Polynomials of Mathematics – Class 9
Answer» Correct choice is (a) (x+9)(x-3) To elaborate: To factorisex^2+6x-27, we have to FIND TWO numbers ‘a’ and ‘b’ such that a+b=6 and ab=27. For that we have to find factors of -27, which are ±1, ±3, ±9. Now we have to ARRANGE two numbers from these numbers such that a+b=6 and ab=27. By considering this, we get two numbers +9 and -3 9 + (-3) = 6 and 9*-3 = -27 Now after manipulating terms, we getx^2+9x- 3x-27. x^2+9x- 3x-27 = x(x+9)-3(x+9) = (x+9)(x-3).

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