What do we get after expanding (p+3q-2z)^2?(a) p^2 + 9q^2 + 4z^2 + 6pq

1.	What do we get after expanding (p+3q-2z)^2?(a) p^2 + 9q^2 + 4z^2 + 6pq – 12qz + 4zp(b) p^2 + 9q^2 + 4z^2 + 12pq + 12qz + 4zp(c) p^2 + 9q^2 + 4z^2 – 12pq – 12qz – 4zp(d) p^2 + 9q^2 + 4z^2 + 6pq – 12qz – 4zpThe question was asked in an interview for internship.This key question is from Factorisation of Polynomials and Algebraic Identities in chapter Polynomials of Mathematics – Class 9
Answer» Right option is (d) p^2 + 9q^2 + 4z^2 + 6PQ – 12qz – 4zp Explanation: We know that (a+b+C)^2 = a^2 + b^2 + c^2 + 2AB + 2BC + 2ca (p+3Q-2z)^2can also be written as (p+3q+(-2z))^2. Here, a = p, b = 3q and c = -2z Therefore, using that formula we get (p+3q+(-2z))^2 = p^2 + (3q)^2 + (-2z)^2 + 2(p)(3q) + 2(3q)(-2z) + 2(-2z)(p) = p^2 + 9q^2 + 4z^2 + 6pq – 12qz – 4zp.

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