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x^2 + 8x + 16 is a multiplier of x+4.(a) True(b) FalseI have been asked this question during an interview for a job.This interesting question is from Remainder Theorem topic in chapter Polynomials of Mathematics – Class 9

Answer»

The correct choice is (a) True

To explain: p(x) is SAID to be multiplier of x-a if p(a) = 0.

Therefore, CHECKING whether p(-4) is ZERO of p(x) or not.

p(-4) = (-4)^2 + 8(-4) + 16

= 16 – 32 +16

= 32 – 32

= 0

p(-4) = 0, so we can SAY that x^2 + 8x + 16 is a multiplier of x+4.

Or in other words, we can say that there we get “0” as a remainder when we divide x^2 + 8x + 16 by x+4.


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