InterviewSolution
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InterviewSolution
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By which velocity a ball be projected vertically upward sothat the distance covered by it in Sth second is twice thedistance it covers in its 6th second (g 10 m/s)(a) 58.8 m/s(c) 65 m/s(b) 49 m/s(d) 19.6 m/s |
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Answer» Things you need to know before we begin: 1. Equations of Kinematicsv = u + ats = ut + 1/2 at^2v^2 - u^2 = 2aswhere,t - timev - velocity at time tu - velocity at time t = 0a - acceleration of the objects - distance traveled in t time 2. Value of Acceleration due to gravity ( 'g' )g = 9.8 m/s^2where,g - acceleration due to gravity Now,Distance covered in nth second = Distance traveled in n seconds - Distance traveled in (n-1) seconds so,Distance covered in nth second (Sn) comes to be,Sn = u + a/2(2n-1) also,a = - gnegative sign represents that the acceleration is opposite to the direction of motion of the object or the velocity of the object. As distance covered in 5th second is twice the distance covered in 6th second we have,S5 = 2(S6)i.e,( u - 9g/2) = 2(u - 11g/2) solving which results in,u = 13g/2 as, g = 9.8 m/s^2 we have,u = 63.7 m/s |
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