1.

C-6. In the figure shown the block B moves down with a velocity 10 m/s. The velocity of A in the positionshown is:(A) 12.5 m/s(B) 25 m/s(C) 6.25 m/s(D) none of these

Answer»

Velocity of B is = 10 ,

so, velocity of string connecting to A , u is given by

10 = (u+0)/2

=>u = 20 m/s

now this Velocity will always be constant along the stringso, velocity of A along the string is u'cos(37) = 20=>>u = 20/(cos37) = 20*5/4 = 25m/s

option B



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