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C-6. In the figure shown the block B moves down with a velocity 10 m/s. The velocity of A in the positionshown is:(A) 12.5 m/s(B) 25 m/s(C) 6.25 m/s(D) none of these |
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Answer» Velocity of B is = 10 , so, velocity of string connecting to A , u is given by 10 = (u+0)/2 =>u = 20 m/s now this Velocity will always be constant along the stringso, velocity of A along the string is u'cos(37) = 20=>>u = 20/(cos37) = 20*5/4 = 25m/s option B |
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