1.

Caculate the electric field due to a dipole on its axial line and equatorial line ​

Answer»

ELECTRIC field due to dipole is given by,

but EA=1/4πEo q/(r+h) 2AND Eb=1/4πEo q/(r-h) 2

as Eb>Ea and act in opposite direction so

E=1/4πEo q/(r-h) 2 - 1/4πEo q/(r+h) 2=1/4πEo q(4rh)/(r2-h2) 2

but q×2h=p,the dipole moment

E =1/4πEo 2pr/(r2-a2)2 (along px)

for short dipole, neglecting A2AS compared to r2, E=2p/4πEor3 I. e. E=p/2πEor3


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