Calcualte the energy released (in joule and `MeV`) in the follwing nulcear reaction: `._(1)^(2)H + ._(1)^(2)H rarr ._(2)^(3)He + ._(0)^(1)n` Assume that the masses of `._(1)^(2)H, ._(2)^(3)He` and neutron `(n)` are `2.0141,3.0160` and `1.0087` respectively in amu.

Calcualte the energy released (in joule and `MeV`) in the follwing nul

1.	Calcualte the energy released (in joule and `MeV`) in the follwing nulcear reaction: `._(1)^(2)H + ._(1)^(2)H rarr ._(2)^(3)He + ._(0)^(1)n` Assume that the masses of `._(1)^(2)H, ._(2)^(3)He` and neutron `(n)` are `2.0141,3.0160` and `1.0087` respectively in amu.
Answer» Correct Answer - `5.223xx10^(3)J, 3.260 MeV`

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Calcualte the energy released (in joule and `MeV`) in the follwing nulcear reaction: `._(1)^(2)H + ._(1)^(2)H rarr ._(2)^(3)He + ._(0)^(1)n` Assume that the masses of `._(1)^(2)H, ._(2)^(3)He` and neutron `(n)` are `2.0141,3.0160` and `1.0087` respectively in amu.

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